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171. Excel Sheet Column Number

Description

Given a string columnTitle that represents the column title as appears in an Excel sheet, return its corresponding column number.

For example:

A -> 1
B -> 2
C -> 3
...
Z -> 26
AA -> 27
AB -> 28 
...

 

Example 1:

Input: columnTitle = "A"
Output: 1

Example 2:

Input: columnTitle = "AB"
Output: 28

Example 3:

Input: columnTitle = "ZY"
Output: 701

 

Constraints:

• 1 <= columnTitle.length <= 7
• columnTitle consists only of uppercase English letters.
• columnTitle is in the range ["A", "FXSHRXW"].

Solutions

• Java
• C++
• Python
• Go
• TypeScript
• C#

• class Solution {
      public int titleToNumber(String columnTitle) {
          int res = 0;
          for (char c : columnTitle.toCharArray()) {
              res = res * 26 + (c - 'A' + 1);
          }
          return res;
      }
  }
  

• class Solution {
  public:
      int titleToNumber(string columnTitle) {
          int res = 0;
          for (char c : columnTitle) {
              res = res * 26 + (c - 'A' + 1);
          }
          return res;
      }
  };
  

• class Solution:
      def titleToNumber(self, columnTitle: str) -> int:
          res = 0
          for c in columnTitle:
              res = res * 26 + (ord(c) - ord('A') + 1)
          return res
  
  

• func titleToNumber(columnTitle string) int {
  	res := 0
  	for _, c := range columnTitle {
  		res = res*26 + int(c-'A'+1)
  	}
  	return res
  }
  

• function titleToNumber(columnTitle: string): number {
      let res: number = 0;
      for (let char of columnTitle) {
          res = res * 26 + char.charCodeAt(0) - 64;
      }
      return res;
  }
  
  

• public class Solution {
      public int TitleToNumber(string columnTitle) {
          int ans = 0;
          foreach (char c in columnTitle) {
              ans = ans * 26 + c - 'A' + 1;
          }
          return ans;
      }
  }
  

All Problems

All Solutions