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168. Excel Sheet Column Title

Description

Given an integer columnNumber, return its corresponding column title as it appears in an Excel sheet.

For example:

A -> 1
B -> 2
C -> 3
...
Z -> 26
AA -> 27
AB -> 28 
...

 

Example 1:

Input: columnNumber = 1
Output: "A"

Example 2:

Input: columnNumber = 28
Output: "AB"

Example 3:

Input: columnNumber = 701
Output: "ZY"

 

Constraints:

  • 1 <= columnNumber <= 231 - 1

Solutions

  • class Solution {
        public String convertToTitle(int columnNumber) {
            StringBuilder res = new StringBuilder();
            while (columnNumber != 0) {
                --columnNumber;
                res.append((char) ('A' + columnNumber % 26));
                columnNumber /= 26;
            }
            return res.reverse().toString();
        }
    }
    
  • class Solution:
        def convertToTitle(self, columnNumber: int) -> str:
            res = []
            while columnNumber:
                columnNumber -= 1
                res.append(chr(ord('A') + columnNumber % 26))
                columnNumber //= 26
            return ''.join(res[::-1])
    
    
  • func convertToTitle(columnNumber int) string {
    	res := []rune{}
    	for columnNumber != 0 {
    		columnNumber -= 1
    		res = append([]rune{rune(columnNumber%26 + int('A'))}, res...)
    		columnNumber /= 26
    	}
    	return string(res)
    }
    
  • function convertToTitle(columnNumber: number): string {
        let res: string[] = [];
        while (columnNumber > 0) {
            --columnNumber;
            let num: number = columnNumber % 26;
            res.unshift(String.fromCharCode(num + 65));
            columnNumber = Math.floor(columnNumber / 26);
        }
        return res.join('');
    }
    
    
  • public class Solution {
        public string ConvertToTitle(int columnNumber) {
            StringBuilder res = new StringBuilder();
            while (columnNumber != 0) {
                --columnNumber;
                res.Append((char) ('A' + columnNumber % 26));
                columnNumber /= 26;
            }
            return new string(res.ToString().Reverse().ToArray());
        }
    }
    
  • impl Solution {
        #[allow(dead_code)]
        pub fn convert_to_title(column_number: i32) -> String {
            let mut ret = String::from("");
            let mut column_number = column_number;
    
            while column_number > 0 {
                if column_number <= 26 {
                    ret.push((('A' as u8) + (column_number as u8) - 1) as char);
                    break;
                } else {
                    let mut left = column_number % 26;
                    left = if left == 0 { 26 } else { left };
                    ret.push((('A' as u8) + (left as u8) - 1) as char);
                    column_number = (column_number - 1) / 26;
                }
            }
    
            ret.chars().rev().collect()
        }
    }
    
    

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