We have a string S
of lowercase letters, and an integer array
shifts
.
Call the shift of a letter, the next letter in the alphabet, (wrapping around so
that 'z'
becomes 'a'
).
For example, shift('a') = 'b'
, shift('t') = 'u'
,
and shift('z') = 'a'
.
Now for each shifts[i] = x
, we want to shift the first i+1
letters
of S
, x
times.
Return the final string after all such shifts to S
are applied.
Example 1:
Input: S = "abc", shifts = [3,5,9] Output: "rpl" Explanation: We start with "abc". After shifting the first 1 letters of S by 3, we have "dbc". After shifting the first 2 letters of S by 5, we have "igc". After shifting the first 3 letters of S by 9, we have "rpl", the answer.
Note:
1 <= S.length = shifts.length <= 20000
0 <= shifts[i] <= 10 ^ 9