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You are given an integer array `nums`

. The **absolute sum** of a subarray `[nums`

is _{l}, nums_{l+1}, ..., nums_{r-1}, nums_{r}]`abs(nums`

._{l} + nums_{l+1} + ... + nums_{r-1} + nums_{r})

Return *the maximum absolute sum of any (possibly empty) subarray of *

`nums`

.Note that `abs(x)`

is defined as follows:

- If
`x`

is a negative integer, then`abs(x) = -x`

. - If
`x`

is a non-negative integer, then`abs(x) = x`

.

**Example 1:**

Input:nums = [1,-3,2,3,-4]Output:5Explanation:The subarray [2,3] has absolute sum = abs(2+3) = abs(5) = 5.

**Example 2:**

Input:nums = [2,-5,1,-4,3,-2]Output:8Explanation:The subarray [-5,1,-4] has absolute sum = abs(-5+1-4) = abs(-8) = 8.

**Constraints:**

`1 <= nums.length <= 10`

^{5}`-10`

^{4}<= nums[i] <= 10^{4}

All contents and pictures on this website come from the Internet and are updated regularly every week. They are for personal study and research only, and should not be used for commercial purposes. Thank you for your cooperation.