You are given an array nums
consisting of non-negative integers. You
are also given a queries
array, where queries[i] = [xi,
mi]
.
The answer to the ith
query is the maximum bitwise
XOR
value of xi
and any element of
nums
that does not exceed mi
. In other words,
the answer is max(nums[j] XOR xi)
for all j
such that nums[j] <= mi
. If all elements in
nums
are larger than mi
, then the answer is
-1
.
Return an integer array answer
where answer.length
== queries.length
and answer[i]
is the answer to
the ith
query.
Example 1:
Input: nums = [0,1,2,3,4], queries = [[3,1],[1,3],[5,6]] Output: [3,3,7] Explanation: 1) 0 and 1 are the only two integers not greater than 1. 0 XOR 3 = 3 and 1 XOR 3 = 2. The larger of the two is 3. 2) 1 XOR 2 = 3. 3) 5 XOR 2 = 7.
Example 2:
Input: nums = [5,2,4,6,6,3], queries = [[12,4],[8,1],[6,3]] Output: [15,-1,5]
Constraints:
1 <= nums.length, queries.length <= 105
queries[i].length == 2
0 <= nums[j], xi, mi <= 109