Given the root
of a binary tree and a leaf
node, reroot
the tree so that the leaf
is the new root.
You can reroot the tree with the following steps for each node cur
on
the path starting from the leaf
up to the
root
excluding the root:
cur
has a left child, then that child becomes cur
's
right child. Note that it is guaranteed that cur
will have at most
one child.
cur
's original parent becomes cur
's left child.Return the new root of the rerooted tree.
Note: Ensure that your solution sets the Node.parent
pointers correctly after rerooting or you will receive "Wrong Answer".
Example 1:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], leaf = 7 Output: [7,2,null,5,4,3,6,null,null,null,1,null,null,0,8]
Example 2:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], leaf = 0 Output: [0,1,null,3,8,5,null,null,null,6,2,null,null,7,4]
Constraints:
[2, 100]
.-109 <= Node.val <= 109
Node.val
are unique.leaf
exist in the tree.