Given the root
of a binary tree, return the lowest common ancestor
(LCA) of two given nodes, p
and q
. If either
node p
or q
does not exist in the tree,
return null
. All values of the nodes in the tree are
unique.
According to the definition
of LCA on Wikipedia: "The lowest common ancestor of two nodes
p
and q
in a binary tree T
is the lowest node
that has both p
and q
as descendants
(where we allow a node to be a descendant of itself)". A
descendant of a node x
is a node y
that
is on the path from node x
to some leaf node.
Example 1:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 1 Output: 3 Explanation: The LCA of nodes 5 and 1 is 3.
Example 2:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 4 Output: 5 Explanation: The LCA of nodes 5 and 4 is 5. A node can be a descendant of itself according to the definition of LCA.
Example 3:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 10 Output: null Explanation: Node 10 does not exist in the tree, so return null.
Constraints:
[1, 104]
.
-109 <= Node.val <= 109
Node.val
are unique.p != q
Follow up: Can you find the LCA traversing the tree, without checking nodes existence?