Given the root of a binary tree, return the lowest common ancestor
(LCA) of two given nodes, p and q. If either
node p or q does not exist in the tree,
return null. All values of the nodes in the tree are
unique.
According to the definition
of LCA on Wikipedia: "The lowest common ancestor of two nodes
p and q in a binary tree T is the lowest node
that has both p and q as descendants
(where we allow a node to be a descendant of itself)". A
descendant of a node x is a node y that
is on the path from node x to some leaf node.
Example 1:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 1 Output: 3 Explanation: The LCA of nodes 5 and 1 is 3.
Example 2:

Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 4 Output: 5 Explanation: The LCA of nodes 5 and 4 is 5. A node can be a descendant of itself according to the definition of LCA.
Example 3:

Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 10 Output: null Explanation: Node 10 does not exist in the tree, so return null.
Constraints:
[1, 104].
-109 <= Node.val <= 109Node.val are unique.p != qFollow up: Can you find the LCA traversing the tree, without checking nodes existence?