You have a browser of one tab where you start on the
homepage
and you can visit another url
, get back in the
history number of steps
or move forward in the history number of steps
.
Implement the BrowserHistory
class:
BrowserHistory(string homepage)
Initializes the object with the
homepage
of the browser.
void visit(string url)
visits url
from the
current page. It clears up all the forward history.
string back(int steps)
Move steps
back in
history. If you can only return x
steps in the history and steps
> x
, you will return only x
steps. Return the
current url
after moving back in history at
most steps
.
string forward(int steps)
Move steps
forward in
history. If you can only forward x
steps in the history and steps
> x
, you will forward only x
steps. Return
the current url
after forwarding in history at
most steps
.
Example:
Input: ["BrowserHistory","visit","visit","visit","back","back","forward","visit","forward","back","back"] [["leetcode.com"],["google.com"],["facebook.com"],["youtube.com"],[1],[1],[1],["linkedin.com"],[2],[2],[7]] Output: [null,null,null,null,"facebook.com","google.com","facebook.com",null,"linkedin.com","google.com","leetcode.com"] Explanation: BrowserHistory browserHistory = new BrowserHistory("leetcode.com"); browserHistory.visit("google.com"); // You are in "leetcode.com". Visit "google.com" browserHistory.visit("facebook.com"); // You are in "google.com". Visit "facebook.com" browserHistory.visit("youtube.com"); // You are in "facebook.com". Visit "youtube.com" browserHistory.back(1); // You are in "youtube.com", move back to "facebook.com" return "facebook.com" browserHistory.back(1); // You are in "facebook.com", move back to "google.com" return "google.com" browserHistory.forward(1); // You are in "google.com", move forward to "facebook.com" return "facebook.com" browserHistory.visit("linkedin.com"); // You are in "facebook.com". Visit "linkedin.com" browserHistory.forward(2); // You are in "linkedin.com", you cannot move forward any steps. browserHistory.back(2); // You are in "linkedin.com", move back two steps to "facebook.com" then to "google.com". return "google.com" browserHistory.back(7); // You are in "google.com", you can move back only one step to "leetcode.com". return "leetcode.com"
Constraints:
1 <= homepage.length <= 20
1 <= url.length <= 20
1 <= steps <= 100
homepage
and url
consist of '.' or lower case
English letters.
5000
calls will be made to visit
, back
,
and forward
.