Given a string s
formed by digits ('0'
- '9'
) and
'#'
. We want to map s
to English lowercase
characters as follows:
'a'
to 'i')
are represented by ('1'
to '9'
) respectively.
'j'
to 'z')
are represented by ('10#'
to '26#'
) respectively.
Return the string formed after mapping.
It's guaranteed that a unique mapping will always exist.
Example 1:
Input: s = "10#11#12" Output: "jkab" Explanation: "j" -> "10#" , "k" -> "11#" , "a" -> "1" , "b" -> "2".
Example 2:
Input: s = "1326#" Output: "acz"
Example 3:
Input: s = "25#" Output: "y"
Example 4:
Input: s = "12345678910#11#12#13#14#15#16#17#18#19#20#21#22#23#24#25#26#" Output: "abcdefghijklmnopqrstuvwxyz"
Constraints:
1 <= s.length <= 1000
s[i]
only contains digits letters
('0'
-'9'
) and '#'
letter.
s
will be valid string such that mapping is always possible.