(This problem is an interactive problem.)
You may recall that an array A
is a mountain array if and only if:
A.length >= 3
i
with 0 < i < A.length -
1
such that:
A[0] < A[1] < ... A[i-1] < A[i]
A[i] > A[i+1] > ... > A[A.length - 1]
Given a mountain array mountainArr
, return the minimum index
such that mountainArr.get(index) == target
. If such an index
doesn't
exist, return -1
.
You can't access the mountain array directly. You may only access
the array using a MountainArray
interface:
MountainArray.get(k)
returns the element of the array at index
k
(0-indexed).
MountainArray.length()
returns the length of the array.Submissions making more than 100
calls to MountainArray.get
will
be judged Wrong Answer. Also, any solutions that attempt to circumvent the
judge will result in disqualification.
Example 1:
Input: array = [1,2,3,4,5,3,1], target = 3 Output: 2 Explanation: 3 exists in the array, at index=2 and index=5. Return the minimum index, which is 2.
Example 2:
Input: array = [0,1,2,4,2,1], target = 3
Output: -1
Explanation: 3 does not exist in the array,
so we return -1.
Constraints:
3 <= mountain_arr.length() <= 10000
0 <= target <= 10^9
0 <= mountain_arr.get(index) <= 10^9