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1890. The Latest Login in 2020

Level

Easy

Description

Table: Logins

+----------------+----------+
| Column Name    | Type     |
+----------------+----------+
| user_id        | int      |
| time_stamp     | datetime |
+----------------+----------+
(user_id, time_stamp) is the primary key for this table.
Each row contains information about the login time for the user with ID user_id.

Write an SQL query to report the latest login for all users in the year 2020. Do not include the users who did not login in 2020.

Return the result table in any order.

The query result format is in the following example:

Logins table:
+---------+---------------------+
| user_id | time_stamp          |
+---------+---------------------+
| 6       | 2020-06-30 15:06:07 |
| 6       | 2021-04-21 14:06:06 |
| 6       | 2019-03-07 00:18:15 |
| 8       | 2020-02-01 05:10:53 |
| 8       | 2020-12-30 00:46:50 |
| 2       | 2020-01-16 02:49:50 |
| 2       | 2019-08-25 07:59:08 |
| 14      | 2019-07-14 09:00:00 |
| 14      | 2021-01-06 11:59:59 |
+---------+---------------------+

Result table:
+---------+---------------------+
| user_id | last_stamp          |
+---------+---------------------+
| 6       | 2020-06-30 15:06:07 |
| 8       | 2020-12-30 00:46:50 |
| 2       | 2020-01-16 02:49:50 |
+---------+---------------------+

User 6 logged into their account 3 times but only once in 2020, so we include this login in the result table.
User 8 logged into their account 2 times in 2020, once in February and once in December. We include only the latest one (December) in the result table.
User 2 logged into their account 2 times but only once in 2020, so we include this login in the result table.
User 14 did not login in 2020, so we do not include them in the result table.

Solution

For each user_id, select the maximum time_stamp as last_stamp. Only select the entries where the values of time_stamp are in the year 2020.

# Write your MySQL query statement below
select distinct user_id, max(time_stamp) as last_stamp
    from Logins
    where date_format(time_stamp, '%Y') = '2020'
    group by user_id;

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